X^2+24x-432=0

Solution for X^2+24x-432=0 equation:

X^2+24X-432=0

a = 1; b = 24; c = -432;
Δ = b2-4ac
Δ = 242-4·1·(-432)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-48}{2*1}=\frac{-72}{2}
=-36
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+48}{2*1}=\frac{24}{2}
=12
$